What to do when chunks get broken?
#4
Suppose the chunk is 70, 40. Let's apply the formula:

r.<floor(ChunkX / 32)>.<floor(ChunkZ / 32)>.mca

"ChunkX / 32" is 70 / 32, which is 2.1875
"ChunkZ / 32" is 40 / 32, which is 1.25

Flooring simply means "remove the fractions", so 2.1875 becomes 2, and 1.25 becomes 1.

Therefore, the file name is:
r.2.1.mca

In other words:
Code:
r.<floor(ChunkX / 32)>.<floor(ChunkZ / 32)>.mca =
r.<floor(70 / 32)>.<floor(40 / 32)>.mca =
r.<floor(2.1875)>.<floor(1.25)>.mca =
r.2.1.mca
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Messages In This Thread
What to do when chunks get broken? - by Jammet - 08-19-2016, 02:33 AM
RE: What to do when chunks get broken? - by xoft - 08-19-2016, 02:46 AM
RE: What to do when chunks get broken? - by LogicParrot - 08-19-2016, 04:20 AM
RE: What to do when chunks get broken? - by xoft - 08-19-2016, 04:02 PM
RE: What to do when chunks get broken? - by xoft - 08-19-2016, 04:04 PM
RE: What to do when chunks get broken? - by xoft - 09-01-2016, 08:19 PM



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